Determination of velocity final for the M(16) Collision onto the top of M(94) for the Total Collapse or demolishment of M(94)

This Poster Graphic explains how to calculate the final Free-Fall velocity of the upper 16 Floor, allegedly falling, and collapsing, and totally demolishing the 94 floor steel tower that is directly below. The Total collapse velocity has to be at least 2,000 miles/hour or 908 meters/second or 3,000 fet/second.
Terminal Velocity is not considered here, but an ideal vacuum condition is assumed, for sake of simplicity. If the Terminal velocity of the M(16) cube reached, is less than the final Free-Fall Velocity, then the required Collapse Energy, (CE(94), cannot be achieved and Total Collapse will not take place.
M(16) had to be dropped from a height of 25 miles to attain this monstrously high value CE(94), that is equivalent to the Energy released by 0.5 Atomic Bombs (Little Boy type), and to gain the, at least, this required Collapse Energy to counter the Resistance and Support Energy of the 94 floor Block or Tower below to remain standing.