Part 1: 100 % In-Elastic Collision of M(14), Top Block, with M(102), Bottom block, in Outer Space to Determine Final Velocity of combined WTC-1 Mass: Result: 1.03 m/s = 2.3 mph, Not 90 m/s or 201 mph

Comment

Comment by Chuck Boldwyn on October 12, 2012 at 10:48am

Error Correction to last post:

Dropping an object from 415 meters, like the top block, M(14) through only air-resistance will yield a final impact collision velocity of 201 mph, as mathematically proven by the following calculation:
v(f) = (2*g*h)^1/2
= [(2)(9.81)(414)]^1/2
= 90.2 m/s
= 201 mph
= OCT claim for
velocity at end of
WTC-1 alleged
collapse.

where, 1 m/s = 2.24 mph

and      1 mph = 0.45 m/s

and     100 mph = 45 m/s

and     200 mph = 90 m/s

and    500 mph = 223 m/s (alleged airplane crash velocity into WTC TT